Double Slit experiment separation

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The discussion centers on calculating the distance between the m=2 bright fringes in a double-slit experiment using the formula y = mλL/d. The user inputs the values for wavelength (600 nm), slit separation (0.1 mm), and distance to the screen (2 m) into the equation. There is confusion regarding the units, as the user initially presents the final answer in mm but questions its validity. Participants emphasize the importance of including units in calculations to ensure the final answer is correctly interpreted. The conversation highlights the need for clarity in unit conversion and proper application of the formula.
Noriko Kamachi
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Homework Statement


A double-spit experiment is performed with light of wavelength 600 nm. A wide viewing screen is 2m behind the grating. What is the distance between the two m=2 bright fringes on the screen? The slit separation given is 0.1 mm.

Homework Equations


Given the wavelength and distance I am assuming y = mλL/d makes the most sense for the equation to solve this problem.

The Attempt at a Solution


I make d=(.1*10^-3)
Wavelength given=600 nm so I make that (600*10^-9)
and my distance and screen are both 2 so I enter the equation as:
y=((2)(2)*(600*10^-9)/(0.1*10^-3)
= (2.4*10^-2) mm as my solution. It looks weird as an answer though. Did I tackle this problem correctly?
 
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Noriko Kamachi said:
I make d=(.1*10^-3)
What are the units for d and all the other numbers you calculated? Why do you say the final answer is in mm?
 
kuruman said:
What are the units for d and all the other numbers you calculated? Why do you say the final answer is in mm?

d is the distance so its unit would be m and i assumed the final answer would be nm because I would be measuring the final distance in terms of wavelength?
 
Noriko Kamachi said:
y=((2)(2)*(600*10^-9)/(0.1*10^-3)
In this equation, put units next to each number and see what comes out.
 
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