Double Slit Interference Question

  • Thread starter iurod
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  • #1
iurod
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Homework Statement



Light of wavelength 680 nm falls on two slits and produces an interference pattern in which thefourth-order fringe is 38 mm from the central fringe on a screen 2.0 m away. What is the separationof the two slits?

Homework Equations


Sin[tex]theta[/tex]=2m([tex]\lambda[/tex]2d)

x=L([tex]\lambda/d[/tex]



The Attempt at a Solution



My givens are:
[tex]\lambda[/tex]= 680nm
L= 2.0m
x438mm

using equation x=L([tex]\lambda/d[/tex] I got:

0.038 = 2.0m(680 x 10-9(4)/d)
d=2.0m(680 x 10-9(4)/d)/0.038)= 1.4x10-4m

Am I doing this correctly?

Thanks.
 

Answers and Replies

  • #2
collinsmark
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I got:

0.038 = 2.0m(680 x 10-9(4)/d)
d=2.0m(680 x 10-9(4)/d)/0.038)= 1.4x10-4m

Am I doing this correctly?
That's how I did it. :approve:
 
  • #3
collinsmark
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I got:

0.038 = 2.0m(680 x 10-9(4)/d)
d=2.0m(680 x 10-9(4)/d)/0.038)= 1.4x10-4m
Oh, except you left the "/d" in there. But I'm guessing that's just a typo. :smile:
 
Last edited:
  • #4
iurod
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Thanks! Definitely a typo, sorry about that.
 

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