1. The problem statement, all variables and given/known data Person weighing 0.9kN rides in an elevator that has downward acceleration of 1m/s^2. What is the magnitude of the force of the elevator floor on the person. Answer in units of kN. 2. Relevant equations F=ma 3. The attempt at a solution I drew a force body diagram and set y upward to be the positive y direction. The relevant forces acting on the person are then 1) -1m/s^2 and 2) -9.8m/s^2 due to gravity and 3) the normal force of the elevator floor that pushes up in the positive y direction. That's the one I am solving for. Sum of the forces in the y direction have to equal each other, right? I have three forces working in the y direction. So F becomes N, the normal force of the elevator yielding: N=ma. I'm guessing a then is just the sum of the two accelerations? So, -9.8 + -1 =-10.8 Then N = 0.9kN(-10.8)....N=-9.72kN?