Downward, find airtime, velocity

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The discussion centers on calculating the airtime and impact velocity of a water balloon thrown downward at an initial velocity of 15 m/s from a height of 25 meters. The correct equation to use is y = y(i) + v(i)t + 1/2gt², where g is the acceleration due to gravity, approximately 9.8 m/s². The airtime ends when the balloon reaches the ground, which occurs when y equals 0. Participants emphasize the importance of understanding the physics concepts before applying equations.

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water balloon thrown down at 15m/s to ground 25 m below, what is air time and velocity at impact
y = y(i) + v(i)sint + 1/2gt2
y = 25 + 15sin(90)t + 1/2(-9.8)t2 ? ?
 
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dude, try to understand the physics before pluging in numbers into a meaningless equation...read the book first...
 
1. What does "air time" MEAN?
2. More specifically, what ends the "air time"?
3. What is y when the "air time" ends?
4. No, not "y = y(i) + v(i)sint + 1/2gt2 "
5. Do you know what sin(90) is?

6. You need to solve an equation to find the time t when "air time" ends.
 
first of all, g is not -9.8. you throw it downwards, not upwards
 

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