Downward, find airtime, velocity

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Homework Help Overview

The discussion revolves around a physics problem involving a water balloon thrown downward with an initial velocity, seeking to determine the airtime and impact velocity as it falls to the ground from a height of 25 meters.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the meaning of "air time" and question what conditions define its end. There are attempts to clarify the equation used and the significance of specific terms, such as the initial velocity and gravitational acceleration.

Discussion Status

The discussion is active, with participants questioning the original poster's understanding of the physics involved and the appropriateness of the equations being used. Some guidance is offered regarding the need to clarify concepts before applying formulas.

Contextual Notes

There are indications of confusion regarding the sign of gravitational acceleration and the interpretation of the initial conditions of the problem. Participants express the need for a clearer understanding of the physics principles at play.

bigman8424
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water balloon thrown down at 15m/s to ground 25 m below, what is air time and velocity at impact
y = y(i) + v(i)sint + 1/2gt2
y = 25 + 15sin(90)t + 1/2(-9.8)t2 ? ?
 
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dude, try to understand the physics before pluging in numbers into a meaningless equation...read the book first...
 
1. What does "air time" MEAN?
2. More specifically, what ends the "air time"?
3. What is y when the "air time" ends?
4. No, not "y = y(i) + v(i)sint + 1/2gt2 "
5. Do you know what sin(90) is?

6. You need to solve an equation to find the time t when "air time" ends.
 
first of all, g is not -9.8. you throw it downwards, not upwards
 

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