Driving Force of 1500 kg Car: 22600 N

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SUMMARY

The driving force required for a 1500 kg racing car accelerating at 5.0 m/s² is calculated to be 22600 N. This force accounts for the lift force of 600 N acting upwards and the grounding effects of 1000 N acting downwards, which influence the normal force. The frictional force, determined by the coefficient of kinetic friction (μk = 1.0), is essential in calculating the net force required to maintain the car's acceleration. The problem emphasizes the importance of understanding how lift and grounding effects impact the overall driving force needed.

PREREQUISITES
  • Understanding of Newton's Second Law (Fnet = ma)
  • Knowledge of friction and its calculation (Friction = μ x normal force)
  • Familiarity with forces acting on vehicles, including lift and grounding effects
  • Basic principles of dynamics in physics
NEXT STEPS
  • Study the calculation of normal force in the presence of lift and grounding effects
  • Learn about the implications of aerodynamic forces on vehicle dynamics
  • Explore the relationship between acceleration, mass, and net force in practical scenarios
  • Investigate the effects of different coefficients of friction on vehicle performance
USEFUL FOR

Students in physics, automotive engineers, and anyone interested in understanding the dynamics of racing cars and the forces acting upon them during acceleration.

moshrom
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Homework Statement


A racing car of mass 1500 kg, is accelerating at 5.0 m/s2, is experiencing a lift force of 600 N [up], due to its streamlined shape, and grounding effects of 1000 N [down], due to air dams and spoilers. Find the driving force needed to keep the car going given that μk = 1.0.


Homework Equations


Friction=μ x normal force, Fnet=ma


The Attempt at a Solution


This is probably an easy problem. I've done everything else on my page, but this one just doesn't make sense for some reason. The question asks for 'the driving force to keep the car going.' I assumed this is the force required to counteract friction minus the force of acceleration... Though I'm probably wrong. The question is either poorly worded or I'm missing something. Why would a net downwards force affect anything?

The given answer is 22600 N. Thanks, all help is appreciated.
 
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Well, the text of the problem wants you to determine the driving force which is needed to accelerate the car at the rate of 5m/s^2, if the normal force is the resultant of gravity, lift and the grounding effects.

ehild
 

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