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Dropping a closed loop into a magbetic field

  1. Nov 15, 2012 #1
    1. The problem statement, all variables and given/known data
    The closed loop is vertical and the magnetic field is a north and south pole such that the looped end faces the magnetic poles.


    A multiple choice question answer stated that the closed loop will have a smaller acceleration than 10mls

    ^2 as it would experience an opposing force. But if I look at it closely, won't the 2 induced force cancel each other so it will accelerate at 10m/s^2?



    2. Relevant equations
    None


    3. The attempt at a solution
    My explanation goes like this: when it is dropped into the magnetic field, it experiences a change in magnetic flux linkage and thus there would be a current induced induced it. since there is a current flowing perpendicular to the magnetic field, by Fleming left hand rule there will be 2 forces acting on the closed loops at the two edges there are equal and opposite. Hence, this cancels out the force which allows the downwards acceleration to be still 10m/s^2.


    Is there something wrong with my concept here? It seems correct to me though. I hope you guys can answer me as soon as possible cos tomorrow is my physics O level paper thanks for the help!
     
  2. jcsd
  3. Nov 15, 2012 #2
    do you have the answer since it's a MCQ?

    Lenz's law?
     
  4. Nov 15, 2012 #3
    The answer is that the acceleration is less than 10m/s^2. But since they cancel out so shouldn't it be 10m/s^2?
     
  5. Nov 15, 2012 #4
    Read about lenz's law about opposing induced force. It satisfied the answer and in actual fact, they do not cancel out.
     
  6. Nov 16, 2012 #5
    Why won't they cancel out? Since the current is the same at both ends?
     
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