Dropping a closed loop into a magbetic field

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Homework Help Overview

The discussion revolves around the behavior of a closed loop dropped into a magnetic field, specifically examining the effects of induced currents and forces on its acceleration. The context involves concepts from electromagnetism, particularly Lenz's law and the interaction between magnetic fields and electric currents.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between induced currents and forces acting on the loop, questioning whether these forces cancel each other out and what impact this has on the loop's acceleration. There is a focus on understanding Lenz's law and its implications for the motion of the loop.

Discussion Status

Some participants have provided insights regarding Lenz's law and its role in explaining the opposing forces experienced by the loop. There is ongoing exploration of whether the induced forces indeed cancel out or contribute to a net opposing force, leading to a smaller acceleration than 10 m/s².

Contextual Notes

Participants are preparing for an upcoming physics examination and are seeking clarification on the concepts involved in the problem. The original poster expresses urgency in obtaining answers due to the impending exam.

sgstudent
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Homework Statement


The closed loop is vertical and the magnetic field is a north and south pole such that the looped end faces the magnetic poles.


A multiple choice question answer stated that the closed loop will have a smaller acceleration than 10mls

^2 as it would experience an opposing force. But if I look at it closely, won't the 2 induced force cancel each other so it will accelerate at 10m/s^2?



Homework Equations


None


The Attempt at a Solution


My explanation goes like this: when it is dropped into the magnetic field, it experiences a change in magnetic flux linkage and thus there would be a current induced induced it. since there is a current flowing perpendicular to the magnetic field, by Fleming left hand rule there will be 2 forces acting on the closed loops at the two edges there are equal and opposite. Hence, this cancels out the force which allows the downwards acceleration to be still 10m/s^2.


Is there something wrong with my concept here? It seems correct to me though. I hope you guys can answer me as soon as possible cos tomorrow is my physics O level paper thanks for the help!
 
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sgstudent said:

Homework Statement


The closed loop is vertical and the magnetic field is a north and south pole such that the looped end faces the magnetic poles.


A multiple choice question answer stated that the closed loop will have a smaller acceleration than 10mls

^2 as it would experience an opposing force. But if I look at it closely, won't the 2 induced force cancel each other so it will accelerate at 10m/s^2?



Homework Equations


None


The Attempt at a Solution


My explanation goes like this: when it is dropped into the magnetic field, it experiences a change in magnetic flux linkage and thus there would be a current induced induced it. since there is a current flowing perpendicular to the magnetic field, by Fleming left hand rule there will be 2 forces acting on the closed loops at the two edges there are equal and opposite. Hence, this cancels out the force which allows the downwards acceleration to be still 10m/s^2.


Is there something wrong with my concept here? It seems correct to me though. I hope you guys can answer me as soon as possible cos tomorrow is my physics O level paper thanks for the help!

do you have the answer since it's a MCQ?

Lenz's law?
 
bsbs said:
do you have the answer since it's a MCQ?

Lenz's law?

The answer is that the acceleration is less than 10m/s^2. But since they cancel out so shouldn't it be 10m/s^2?
 
Read about lenz's law about opposing induced force. It satisfied the answer and in actual fact, they do not cancel out.
 
bsbs said:
Read about lenz's law about opposing induced force. It satisfied the answer and in actual fact, they do not cancel out.

Why won't they cancel out? Since the current is the same at both ends?
 

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