Dy/dx = (y^2) /x , form differential equation

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SUMMARY

The differential equation dy/dx = (y^2)/x was analyzed, leading to the conclusion that the user's solution y = -1/(ln x - c) is correct, while the provided answer (-1/ln x) + C is incorrect. The discussion emphasized the importance of using ln|x| in the antiderivative and suggested that the constant should be incorporated into the denominator. The correct form of the solution is y = -1/(ln Kx), where K is an arbitrary constant.

PREREQUISITES
  • Understanding of differential equations and their solutions
  • Familiarity with logarithmic functions, specifically ln|x|
  • Knowledge of arbitrary constants in mathematical solutions
  • Ability to verify solutions by substituting back into the original equation
NEXT STEPS
  • Study the properties of logarithmic functions, focusing on ln|x|
  • Learn about solving first-order differential equations
  • Explore the concept of arbitrary constants in mathematical expressions
  • Practice verifying solutions of differential equations through substitution
USEFUL FOR

Students studying calculus, particularly those focusing on differential equations, as well as educators and tutors seeking to clarify common misconceptions in solving such equations.

goldfish9776
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Homework Statement


my ans is lnx = (-1/y) + c
(-1/y) = lnx -c
y = -1/ (lnx -c ) , but the answer given is (-1/ln x )+ C , how to get the answer given ?

Homework Equations

The Attempt at a Solution

 
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Your solution seems fine. I believe the given answer may be wrong.
 
You can easily verify that your answer is correct and the given answer is wrong by plugging them back into the original DE. By the way, you should post the original DE in the body, not the title of your post.

The only thing I would change is use ##\ln |x|## in the antiderivative.
 
goldfish9776 said:

Homework Statement


my ans is lnx = (-1/y) + c
(-1/y) = lnx -c
y = -1/ (lnx -c ) , but the answer given is (-1/ln x )+ C , how to get the answer given ?

Homework Equations

The Attempt at a Solution

When you post a question, please put the problem statement into the first section, not the thread title.

Your answer looks fine to me, except that it should be ln|x|, but you should carry it a step further and solve for y. The given answer should have the constant in the denominator, not just added to the fraction as you show it.
 
And more often than not for a result like that you would be writing, since c is an arbitrary constant

y = -1/(ln x + ln K) where K is another arbitrary constant

= -1/(ln Kx) and thence maybe

x = K' e-y
 

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