# Dynamic reaction versus Coriolis acceleration of the disk

• MPavsic
In simple terms, it is a way of describing a system in which all the forces and moments are combined. In this case, the forces are the centrifugal force and the gravitational force on the object, and the moment is the perpendicular distance between the axis of rotation and the line of action of the force.

#### MPavsic

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I have mind boggling problem, trying to distinguish between Dynamic reaction versus Coriolis acceleration of thin hoop.

Problem: A thin, hoop of mass m and radius r spins at the constant rate ω 1 about an axle held by a fork-ended vertical rod, which rotates at the constant rate ω 2. The mass of spokes and spindle are negligible.

1. Determine Coriolis acceleration of point P at the edge of the hoop, when point P is aligned with vertical axis of the rod.

2. Determine acceleration produced by gyroscopic couple of the hoop on axle held by a fork-ended vertical rod, where support of the axle by the rod equals to radius of point P on each side of the hoop.

To solve Coriolis I am using equation ac = 2 omega1 omega2 *r.

To solve acceleration of gyroscopic couple I am using C = I omega1 omega2 / r, where mass to compute inertia = 1kg.

The question is:

Why is Coriolis acceleration doubled in comparison with gyroscopic acceleration? Both are causing the same effect of force and torque consequentially.

Where do i have problem in my calculations?

Last edited by a moderator:
MPavsic said:
<< Thread moved from the technical forums, so no Homework Help Template is shown >>

I have mind boggling problem, trying to distinguish between Dynamic reaction versus Coriolis acceleration of thin hoop.

Problem: A thin, hoop of mass m and radius r spins at the constant rate ω 1 about an axle held by a fork-ended vertical rod, which rotates at the constant rate ω 2. The mass of spokes and spindle are negligible.

1. Determine Coriolis acceleration of point P at the edge of the hoop, when point P is aligned with vertical axis of the rod.

2. Determine acceleration produced by gyroscopic couple of the hoop on axle held by a fork-ended vertical rod, where support of the axle by the rod equals to radius of point P on each side of the hoop.

To solve Coriolis I am using equation ac = 2 omega1 omega2 *r.

To solve acceleration of gyroscopic couple I am using C = I omega1 omega2 / r, where mass to compute inertia = 1kg.

The question is:

Why is Coriolis acceleration doubled in comparison with gyroscopic acceleration? Both are causing the same effect of force and torque consequentially.

Where do i have problem in my calculations?

I am working on some calculations for my RC model. Wel
MPavsic said:
<< Thread moved from the technical forums, so no Homework Help Template is shown >>

I have mind boggling problem, trying to distinguish between Dynamic reaction versus Coriolis acceleration of thin hoop.

Problem: A thin, hoop of mass m and radius r spins at the constant rate ω 1 about an axle held by a fork-ended vertical rod, which rotates at the constant rate ω 2. The mass of spokes and spindle are negligible.

1. Determine Coriolis acceleration of point P at the edge of the hoop, when point P is aligned with vertical axis of the rod.

2. Determine acceleration produced by gyroscopic couple of the hoop on axle held by a fork-ended vertical rod, where support of the axle by the rod equals to radius of point P on each side of the hoop.

To solve Coriolis I am using equation ac = 2 omega1 omega2 *r.

To solve acceleration of gyroscopic couple I am using C = I omega1 omega2 / r, where mass to compute inertia = 1kg.

The question is:

Why is Coriolis acceleration doubled in comparison with gyroscopic acceleration? Both are causing the same effect of force and torque consequentially.

Where do i have problem in my calculations?

The main problem was, that I did not understand the Moment Copule which is by definition: "Couple is a system of two forces which are equal in magnitude, opposite in direction and have parallel lines of action."