1. The problem statement, all variables and given/known data 2200kg beam is sitting on two rollers spaced 2m apart. rollers weigh 1200kg and have radius of .35m. the block is pulled to the right with 4000N. there is no slippage. find the acceleration of the system (answer given is one of the rollers). 2. Relevant equations I of circular roller =(mR^2)/2 3. The attempt at a solution i am trying to draw the FBD for the roller and am just confused my it. it is hard to get any equations to solve this problem without a FBD. can the mg of the roller be assumed to be (1100+1200)9.81 from the center of gravity? super confused. our teacher teaches us a little differently, draw FBD. find kinetic equations. then find kinematic equations. i assume once i have the FBD correct and i understand the system i will find the velocity and and angular velocity of the point of the roller that touches the beam from the center of the roller and from the instantaneous center of the roller that touches the ground? then use that data to find the acceleration? answer given is acceleration of roller is 1.29m/sec^2 this is a study guide so any help would be appreciated. asked in the advanced thread... but i think it wasn't advanced enough.