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Dynamics - Another collision question

  • Thread starter Chantry09
  • Start date
61
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1. Homework Statement

http://img291.imageshack.us/img291/7829/collisionok5.jpg [Broken]

2. Homework Equations

Conservation of momentum
Conservation of Kinetic Energy
GPE
KE

3. The Attempt at a Solution

Ive done the first part of the question. With the second part, i thought about it this way:

If the ram is seen to have zero velocity just after impact then all of the rams kinetic energy must have been transphered to the pile, no?

In which case, having worked out the gravitational potential energy in the ram initially to be 5886J. The kinetic energy in the pile must be:

5886 = 0.5 x 300 x V^2
39.24 = V^2
6.26 = V

However apparently the answer *should* be 7.23 m/s.

Can someone tell me where i have gone wrong?

James
 
Last edited by a moderator:

Answers and Replies

Doc Al
Mentor
44,828
1,084
Your mistake is in assuming that KE is conserved.
 
61
0
Ok. I worked out that the block would be travelling at 5.42m/s when it strikes the pile (using V^2= U^2 + 2as).

Now i know original momentum of the ram = 400 x 5.42 = 2168
Now if momentum is conservered: 2168 = 300 x V
V = 7.23 m/s

Oh, thats right....whoops. Thank you.
 

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