Conceptual Collision Question -- What

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SUMMARY

The discussion centers on the collision between two balls, A and B, where Ball A of mass ma strikes Ball B of mass mb, initially at rest. The derived expression for the final velocity of Ball A after the collision is vaf = vao / (cosθ + sinθcotφ), which intriguingly shows independence from the masses of the balls. Participants highlight the importance of the Law of Conservation of Linear Momentum in understanding the collision dynamics and emphasize that while the final velocity of Ball A is mass-independent, the mass of Ball B influences the angles of departure post-collision.

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  • Understanding of the Law of Conservation of Linear Momentum
  • Basic knowledge of vector components in physics
  • Familiarity with trigonometric functions, specifically sine and cosine
  • Concept of collision dynamics in classical mechanics
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golf20
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1. Question: Ball A of mass ma is traveling along the x-axis with velocity vao when it strikes Ball B of mass mb, which is at rest. After the collision, Ball A travels at an angle θ above the x-axis and Ball B travels at an angle φ below the x-axis. The final velocities of Balls A and B are vaf and vbf, respectively. Write an expression that gives the velocity of Ball A, vaf, after the collision.

2. Relevant Info: Law of Conservation of Linear Momentum

3. Solution: The expression I get for vaf is vao / (cosθ + sinθcotφ). I find this expression strange because it shows that vaf is independent of the masses of Balls A and B. However, the expression for vbf does include mass. I do not understand how this makes sense conceptually -- Could someone provide an explanation?
 
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golf20 said:
1. Question: Ball A of mass ma is traveling along the x-axis with velocity vao when it strikes Ball B of mass mb, which is at rest. After the collision, Ball A travels at an angle θ above the x-axis and Ball B travels at an angle φ below the x-axis. The final velocities of Balls A and B are vaf and vbf, respectively. Write an expression that gives the velocity of Ball A, vaf, after the collision.

2. Relevant Info: Law of Conservation of Linear Momentum

3. Solution: The expression I get for vaf is vao / (cosθ + sinθcotφ). I find this expression strange because it shows that vaf is independent of the masses of Balls A and B. However, the expression for vbf does include mass. I do not understand how this makes sense conceptually -- Could someone provide an explanation?
Try letting B have an initial velocity vboalong the x axis. That should restore the symmetry. I think you will see then that when one initial velocity goes to zero the masses disappear from the after velocity of the other ball.
This does mot mean that the mass of the resting ball is immaterial. If you were to run the same experiment, just changing that mass, the departure angles would change.
 
My understanding is that the angle at which these bodies move after collision is actually taking into consideration, their mass. I'm not sure about this though.
 

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