Dynamics: Moving wedge with mass on it

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To keep the small block of mass "m" fixed on the sloping side of the triangular block of mass "M," a force "F" must be applied to "M." The required force is calculated as F = (m+M)g*tan(THETA), where g is the acceleration due to gravity. The discussion highlights the role of pseudo forces in determining the acceleration of the wedge-mass system. It clarifies that the projection of the force on "m" along the wedge surface must balance the gravitational force acting on "m." Understanding these dynamics is crucial for solving the problem accurately.
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Homework Statement


Small block of mass "m" rests on sloping side of triangular block of mass "M" which itself rests on table. Assuming all surfaces are frictionless, determine force "F" that must be applied to "M" so that "m" remains fixed. Wedge incline is "THETA"

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The Attempt at a Solution


attached is picture. I don't know where to start, so no attempted solution. The answer is:
F = (m+M)g*tan(THETA). i don't see why the mass on the wedge would move up the ramp if a force is applied to the left of the wedge.

where g is acceleration due to gravity
 

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Because of the pseudo force. If a pseudo force F is applied to the wedge, then the acceleration of the wedge+mass system is F/(M+m) and the force on m is mF/(M+m). The projection of that force along the surface of the wedge is equal to the gravitational force acting along the surface of the wedge.
 
k solved it thanks
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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