Dynamics Question-Parabolic Coordinates

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SUMMARY

This discussion focuses on the application of parabolic coordinates defined by \(\xi = r + x\) and \(\eta = r - x\) in a two-dimensional system. The user successfully derived expressions for kinetic energy, specifically \(T = \frac{m}{8}(\xi + \eta)\left(\frac{\dot{\xi}^2}{\xi} + \frac{\dot{\eta}^2}{\eta}\right)\), and identified the relationships between \(\xi\), \(\eta\), \(x\), and \(y\). The user also inquired about the appropriate form of potential energy in this context, questioning whether it should be treated as gravitational potential energy. The discussion emphasizes the importance of correctly interpreting the variables and equations in the Lagrangian and Hamiltonian frameworks.

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  • Understanding of parabolic coordinates in physics
  • Familiarity with Lagrangian and Hamiltonian mechanics
  • Knowledge of kinetic and potential energy formulations
  • Basic algebraic manipulation skills for equations
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  • Study the action integral formalism in Lagrangian mechanics
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Students and professionals in physics, particularly those studying classical mechanics, Lagrangian dynamics, and coordinate transformations. This discussion is beneficial for anyone looking to deepen their understanding of parabolic coordinates and their applications in motion equations.

QuantumLuck
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Homework Statement



I am told that parabolic coordinates in a plane are defined by \xi = r + x and \eta = r - x. after this i am then asked to show that this leads to a given expresion for the kinetic energy (if i knew x and y i could find this without a problem). From this I am then told to find the equations of motion, an expression which i find very vague. I am in fact familiar with the Lagrangian and Hamiltonian formalisms (loosely) but I do not know what my expression for potential energy will be in this system (if i am on the right track here). Anyway, the main problem I am having at the moment is that I am very unsure as to what "r" is. Any help would be greatly appreciated.
 
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Is this a two-dimensional problem (i.e. what system are you looking at)? If so, then my guess is that r=\sqrt{x^2+y^2}. From this, you could invert the equations and then recast your Lagrangian (or Hamiltonian) in these two new coordinates (since you should know what L=T-V looks like in Cartesian coordinates already). Maybe an obvious expansion will present itself when you see it in these new variables.
 
cipher42 said:
Is this a two-dimensional problem (i.e. what system are you looking at)? If so, then my guess is that \sqrt{x^2+y^2}. From this, you could invert the equations and then recast your Lagrangian (or Hamiltonian) in these two new coordinates (since you should know what L=T-V looks like in Cartesian coordinates already). Maybe an obvious expansion will present itself when you see it in these new variables.

so yeah i think this is right. so here is what i did; \xi = \sqrt{x^2+y^2}+x and then i squared both sides to obtain \xi^{2} = 2x^{2} + y^{2} + 2x \sqrt{x^2+y^2} and \eta^{2} = 2x^{2} + y^{2} -2x \sqrt{x^2+y^2} so now that i have these equations i have been playing around with them trying to look for a way to separate out the x and the y terms so i can get x and y in terms of \xi and \eta. the various i have tried to do this is to add and subtract these equations to each other, each resulting in a varying degree of failure. not sure where to go from here, if i have even went about this correctly.
 
QuantumLuck said:
so yeah i think this is right. so here is what i did; \xi = \sqrt{x^2+y^2}+x and then i squared both sides to obtain \xi^{2} = 2x^{2} + y^{2} + 2x \sqrt{x^2+y^2} and \eta^{2} = 2x^{2} + y^{2} -2x \sqrt{x^2+y^2} so now that i have these equations i have been playing around with them trying to look for a way to separate out the x and the y terms so i can get x and y in terms of \xi and \eta. the various i have tried to do this is to add and subtract these equations to each other, each resulting in a varying degree of failure. not sure where to go from here, if i have even went about this correctly.

oops I am dumb. clearly to find x i take \xi - \eta to find that \xi - \eta \ = 2x and as such \ x = (1/2)\xi - \eta so i then plug in x and find that \ y =\sqrt{\xi\eta} at which point i then showed that kinetic energy \ T=(m/8)(\xi+\eta)(\dot{\xi}^2/\xi +\dot{\eta}^2/\eta). the final thing that i now have to do for this problem is to write down the equations of motion. now since this is for a particle am i assuming that the potential energy is varying solely as a gravitational potential? it is not obvious to me at all. or rather should i go through the action integral formalism for this coordinate system?
 
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