Dynamics Question (water falling from the side of a tank)

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SUMMARY

The discussion focuses on a dynamics problem involving water flowing from a hole in a tank. The tank has a water level of 10 meters, with the hole positioned 1 meter below the surface. Participants analyze the projectile motion of the water, applying equations of motion to determine the horizontal distance from the tank where the water will land. Key insights include the need to calculate the initial speed of the water as a function of the hole height and the horizontal distance as a function of that height.

PREREQUISITES
  • Understanding of projectile motion and kinematics
  • Familiarity with equations of motion: y = y0 + 1/2 gt^2 and t = v(y)/g
  • Knowledge of fluid dynamics principles, particularly steady flow
  • Ability to calculate kinetic energy in fluid systems
NEXT STEPS
  • Calculate the initial speed of water as a function of hole height using Bernoulli's principle
  • Explore the relationship between height and horizontal distance in projectile motion
  • Study the effects of different hole heights on the trajectory of fluid discharge
  • Investigate the principles of steady flow in fluid dynamics
USEFUL FOR

Students in physics, particularly those studying dynamics and fluid mechanics, as well as educators looking for practical examples of projectile motion and fluid flow principles.

CloudDreamer7
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[SOLVED] Dynamics Question (water falling from the side of a tank)

Homework Statement


A large tank rests on the ground and has a water level 10 m above the ground. Water issues from a small hole in the side, 1 m below the the surface of the water. How far from the side of the tank will the water hit the ground ? Is there another height at which if a hole were drilled there, the water from it would reach the ground at the same point? Justify ur answer.



The Attempt at a Solution


as every logical person i assumed that water falls in projectile manner so on the x -axis you have x = v(x)t where x is the position where the water hits the ground, v(x) is the x-component of velocity and t is time; on the y-axis you have accelerated motion and so you have 2 eqns :

y = y0 + 1/2 gt^2 and t = v(y)/g

where v(y) is the y - component of velocity, y is the height, and y0 is the starting point.

i found the time t from here but i fail to go any further because i don't know how to get v(x) or sth that can help me find v(x).

Now this might not seem like an undergraduate problem but i am in 2nd yr and we are having sth like a general physics paper as a revision kinda thing. so this is in reality 1st yr dynamics staff. And its weird that i can't solved it because i used to be good in these. *sigh*
 
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Assume that the water issues from the hole horizontally.

Hints: Find the initial speed as a function of hole height (h). Then try to find the horizontal distance as a function of h.
 
Welcome to PF!

CloudDreamer7 said:
A large tank rests on the ground and has a water level 10 m above the ground. Water issues from a small hole in the side, 1 m below the the surface of the water.

Hi CloudDreamer7! Welcome to PF! :smile:

It can't make any difference whether there's a great big tank or just a curved pipe which finishes horizontally and which happens to be 1m from top to horizontal outlet.

In steady flow, I think it doesn't make any difference whether the water comes continuously, or comes in "bullets".

So work out the kinetic energy for a bullet of water falling 1m. :smile:
 

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