E field in a wire

  • Context: Undergrad 
  • Thread starter Thread starter Jonathan Apps
  • Start date Start date
Click For Summary
SUMMARY

The electric field (E field) along a path through air from the positive to the negative end of a battery exhibits a dipole field, centered midway between the terminals. In contrast, when a wire connects the battery terminals, the E field at large distances diminishes rapidly to zero due to the short circuiting effect. The difference in E field behavior is primarily caused by current flow, which alters surface charge distribution and influences the electric field in the wire according to Ohm's law. The conductivity of the wire material also plays a crucial role in determining the E field strength.

PREREQUISITES
  • Understanding of electric fields and dipole fields
  • Familiarity with Ohm's law and its local form
  • Knowledge of surface charge distribution in conductive materials
  • Basic principles of battery operation and internal resistance
NEXT STEPS
  • Research the principles of electric dipoles and their fields
  • Study the relationship between conductivity and electric field strength in materials
  • Explore the effects of surface charge on electric fields in conductors
  • Learn about the implications of short circuits in electrical circuits
USEFUL FOR

Electrical engineers, physics students, and anyone interested in understanding the behavior of electric fields in conductive materials and their applications in circuit design.

Jonathan Apps
Messages
5
Reaction score
5
1. What is the electric field along a path through the air that starts at the + end of a battery, ends at the - end, and goes a large distance from the battery? In particular, what is the E field at those large distances?

2. Replace the path in 1. by the same path but along a wire between the + and - ends. What is the E field at large distances now?

3. And the point of this post is...... what causes the difference?
 
Physics news on Phys.org
Say you extend parallel wires from the ends of battery, plus minus charges distribute on their surface and change E, V around from what they used to be. Zero E inside the wire metal material. Then say you short circuit at the ends of the wires with a resister, by Ohm’s law points on it undertakes voltage in accordance with V of space around. If loop wire has homogeneous resistance, another pattern of wire surface charge distribution and E, V in space take place.


Image_20250814_0001.webp
 
Last edited:
1. It is more or less an electric dipole field that decreases with distance

2. It is the value of electric field allowed by the constitutive relation in the material of the wire, that is Ohm's law in its local form. It could be very high if the conductivity of the wire is low (compatible with what the battery can supply due to its internal resistance)

3. Surface charge (and interface charge, if you change the material the wire is made of). It shapes the field inside the wires in such a way that it will follow the geometry and the constitutive relation.

See this https://electronics.stackexchange.c...ectric-field-in-a-wire-constant/532550#532550
 
Jonathan Apps said:
3. And the point of this post is...... what causes the difference?
1. In the first case, no current flows through air, so the E-field will be a dipole field, centred halfway along the axis between the battery terminals.
2. In the second case, the battery is short-circuited by the wire, so there is almost no external E-field, rapidly falling to zero as the battery becomes discharged.
3. What causes the difference? Current flow.
 
  • Like
Likes   Reactions: sophiecentaur

Similar threads

  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 36 ·
2
Replies
36
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 21 ·
Replies
21
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 27 ·
Replies
27
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K