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goldust
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E = mc^2 results in c^2 = E / m, and division by 0 is undefined.
Done.goldust said:Oops, my bad. Should be in the Special & General Relativity section.
goldust said:E = mc^2 results in c^2 = E / m, and division by 0 is undefined.
Nugatory said:##E=mc^2## is a special case of the more general ##E^2=(m_0{c}^2)^2+(pc)^2##. The massless particles have ##m_0## equal to zero but ##p## non-zero.
goldust said:E = mc^2 results in c^2 = E / m, and division by 0 is undefined.
Not in general. Photons have momentum but 0 mass, and for massive objects momentum is unbounded as v approaches c.ModestyKing said:Yet momentum is m * v, mass times velocity.
According to Einstein's famous equation, E = mc^2, energy and mass are equivalent because they are different forms of the same thing. In other words, mass can be converted into energy, and vice versa. This concept is known as mass-energy equivalence.
No, not all objects with mass can be converted into pure energy. The conversion of mass into energy requires a very specific process, such as nuclear fission or fusion, which only occurs in extreme conditions.
While it may seem counterintuitive, it is possible for some particles to have zero mass. These particles, such as photons, have energy but no rest mass. Therefore, their mass in the E = mc^2 equation is equal to zero, resulting in the equation E = 0.
Yes, E = mc^2 can be applied to everyday objects, but the amount of energy produced would be minuscule. This equation is more commonly used in the study of subatomic particles and nuclear reactions.
Einstein's famous equation was a result of his theory of special relativity, which he developed through thought experiments and mathematical equations. He realized that energy and mass were equivalent and could be converted into each other, leading to the famous equation E = mc^2.