E. Potential Energy: Uniformly Charged Hollow Sphere and Point Charge

Click For Summary

Discussion Overview

The discussion revolves around the electric potential energy between a uniformly charged hollow sphere and a point charge, particularly at the surface of the hollow sphere. Participants explore the implications of the shell theorem and the conditions under which the potential energy formula applies, questioning whether the shape of the object affects the potential energy calculation.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests that the electric potential energy formula assumes the hollow sphere behaves like a point charge, raising questions about the dependence on the object's physical properties.
  • Another participant emphasizes the need for clarity on the definitions of the variables involved (q_1, q_2, and r) to follow the argument confidently.
  • A participant points out that the formula for electric potential energy can be generalized for systems of point charges, regardless of their distribution.
  • There is a discussion about the validity of the potential energy formula when the distance from the center of the sphere (R) is greater than or less than the radius of the sphere (r), with specific expressions provided for each case.
  • One participant references the shell theorem, noting that it applies only to spherically symmetric charge distributions, which may influence the potential energy calculations.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the applicability of the potential energy formula under different conditions, particularly concerning the shape of the charge distribution. Multiple competing views remain about the implications of the shell theorem and the definitions of the variables involved.

Contextual Notes

Limitations include the lack of clarity on the definitions of the variables q_1, q_2, and r, as well as the assumptions regarding the shape of the charge distribution and its impact on the potential energy calculation.

Heisenberg7
Messages
101
Reaction score
18
I was doing a problem with this one detail. It says that the electric potential energy of an uniformly charged hollow sphere and a point charge is (at the surface of the hollow sphere; both positive): $$U = k \frac{q_1 q_2}{r}$$ I guess this assumes that the hollow sphere is a point charge. Now my question is, does the electric potential energy depend on other physical properties of an object? Or is this like the Newton's Shell Theorem? What if the object wasn't spherical?
 
Physics news on Phys.org
Heisenberg7 said:
I guess this assumes that the hollow sphere is a point charge.
You do not tell us what are q_1,q_2 and r so that we can follow your guess condifently.
BTW
U=k \sum_{i<j}\frac{q_iq_j}{r_{ij}}
is a fundamental rule for system of point charges whatever distributions they have.
 
Last edited:
anuttarasammyak said:
You do not tell us what are q_1,q_2 and r so that we can follow your guess condifently.
Charge of the sphere and the point charge respectively. ##r## is the radius of the sphere. Now, in general, does it hold if ##R > r## (where ##R## represents the distance from the center)?
 
By the shell theorem, the field outside any spherically symmetric charge distribution is the same as that of a point charge with the same total charge at the center of the sphere. Yes, this is only true for spherically symmetric distributions.
 
  • Like
Likes   Reactions: Heisenberg7
Heisenberg7 said:
Now, in general, does it hold if R>r (where R represents the distance from the center)?
U(R)=k\frac{q_1q_2}{R} for R > r
U(R)=k\frac{q_1q_2}{r} for R < r
 
  • Like
Likes   Reactions: Heisenberg7

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
23
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K