Eliminating Alcohols: Why Do (A) and (B) Give Different Products?

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SUMMARY

The discussion focuses on the elimination reactions of compounds (A) and (B), specifically analyzing the products formed. Compound (A) yields 1-pentene (minor) and 2-pentene (major), including its E-Z diastereomers, resulting in three possible products. In contrast, compound (B) produces only the E and Z diastereomers of 2-pentene, leading to two possible products. The confusion arises from the assignment of stereochemistry, where (A) is labeled as (r) and (B) as (s), prompting questions about the accuracy of the provided information.

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baldbrain
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Homework Statement
I just have a problem with (A) & (B)
IMG_20180719_173721.JPG

The attempt at a solution
Analysing all possible products;
(A) can give 1-pentene (minor) + 2-pentene (major). But you also have the E-Z diastereomers of 2-pentene. So that's total 3 possible products.
(B) will give only the diastereomers E & Z 2-pentene. So 2 possible products
Hence, (A)→(s) & (B)→(r)
But they've given (A)→(r) & (B)→(s)
How can it be?
 

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Physics news on Phys.org
Books are not infallible.
 
Are you sure? No hitch? We aren't missing anything?
 
Nope. S, R, Q, P.
 
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