Earth and Sun - Gravity problem

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SUMMARY

The discussion focuses on calculating the mass of the Sun and comparing its density to that of Earth using gravitational equations. The Sun's mass is determined to be 2.0 x 1030 kg, derived from the gravitational formula Fg = G*m1*m2/r2. Additionally, it is established that the density of the Sun is one-fourth that of Earth, represented as Psun = 1/4 Pearth. The participants explore the application of gravitational constants and ratios in these calculations.

PREREQUISITES
  • Understanding of gravitational force equations, specifically g = G*m/r2
  • Familiarity with mass and density concepts in physics
  • Knowledge of the gravitational constant (G)
  • Basic understanding of orbital mechanics
NEXT STEPS
  • Study the gravitational constant (G) and its applications in astrophysics
  • Learn about density calculations and comparisons in celestial bodies
  • Research orbital mechanics and the factors affecting planetary orbits
  • Explore advanced gravitational equations and their implications in astrophysics
USEFUL FOR

Students studying physics, particularly those focusing on gravitational forces and celestial mechanics, as well as educators seeking to enhance their understanding of mass and density comparisons in astronomy.

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Homework Statement


Earth is a satellite of the sun with an orbit radius of approximately 1.5 x 10^11 m.

a) What is the Sun's mass? **Answer:** 2.0 x 10^30 kg

b) If the Sun's radius is 6.96 x 10^8 m, how does the Sun's density compare with Earth's density? **Answer:** Psun = 1/4 Pearth

Homework Equations



g = G*m/r^2 and Fg = G*m1*m2/r^2

The Attempt at a Solution



a) So G*m1*m2/r^2

G*(m of the earth)*(mass of the sun)/radius^2

I put these values in but didn't get the answer?

b) I don't know how to do this one? Would I just see what fraction of the Sun's radius is the Earth's and that's similar to the density?
 
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