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The astronaut orbiting the Earth in Figure P4.32 is preparing to dock with a Westar VI satellite. The satellite is in a circular orbit 470. km above the Earth's surface, where the free-fall acceleration (centripetal acceleration) is 8.19 m/s2. Take the radius of the Earth as 6370 km.
Determine the speed of the satellite in km/h.
THis is a circular motion problem where a = v^2/r can be used right?
8.19 m/s^2 converted to km/h^2 = 1061.42 km/h^2
sqrt(1061.424*(470+6370) = 2694.46
my answer was 2694.46; 2690 but the system is telling me that I'm off by a multiple of ten. What am I doing wrong?
Determine the speed of the satellite in km/h.
THis is a circular motion problem where a = v^2/r can be used right?
8.19 m/s^2 converted to km/h^2 = 1061.42 km/h^2
sqrt(1061.424*(470+6370) = 2694.46
my answer was 2694.46; 2690 but the system is telling me that I'm off by a multiple of ten. What am I doing wrong?