Easy conceptual mechanics question

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When a ball and a stretched object like a telephone pole fall from the same height, the force they exert upon hitting the ground is influenced by their stopping time and velocity at impact. The formula F = Δp/t highlights that force is related to momentum change over time. A softer object, like a pillow, compresses and takes longer to stop, resulting in lower force compared to a harder object like a basketball, which stops quickly and exerts greater force. If the stretched ball and the pole have similar stopping times upon impact, they will exert equal force despite their different shapes. Understanding these dynamics involves concepts like acceleration and momentum conservation.
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Just a random question i had in mind. should be very simple to answer. Assume I had a ball of some arbitrary mass (m), and dropped this ball from an arbitrary height (h). Now assume i had stretched out this mass to look something like a pole (lets just say a telephone pole). Now let's say this telephone pole fell (as you would imagine a tree falling) from the same height(h). would they both exert the same force once they hit the ground? what other relationships can i apply to these 2 objects? (acceleration, momentum, etc...?)
An explanation with some concepts would be great..maybe F=ma or conservation of momentum can be applied? Anyways..thanks in advance
 
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The force an object exert when hitting the ground after falling is dependent on the amount of time it took the object to stop (or bounce back) and the velocity at the collision.
F = \frac{\Delta p}{t} where p is momentum and t is time.
For example, when a pillow falls down and hit the floor it 'compresses' and this compression takes plenty of time so the force felt isn't that high. Take an object of similar mass to a pillow, say a basketball and the force exerted by it is much higher because the basketball bounces very fast compared to the pillow, thus the force is much greater.

Answering your question, when you stretch your ball you are probably changing its physical properties and probably it will not bounce the same way and in the same time as the ball, but if you manage to make it stop once it reaches ground in the same time the ball stops once it reaches ground, then the force exerted will be equal.
 
I built a device designed to brake angular velocity which seems to work based on below, i used a flexible shaft that could bow up and down so i could visually see what was happening for the prototypes. If you spin two wheels in opposite directions each with a magnitude of angular momentum L on a rigid shaft (equal magnitude opposite directions), then rotate the shaft at 90 degrees to the momentum vectors at constant angular velocity omega, then the resulting torques oppose each other...

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