Easy differential equation but i am stuck

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SUMMARY

The general solution to the differential equation tv' + v = 0 is v(t) = c/t, as stated in the textbook. The user attempted to solve it by rewriting it as v' + (1/t)v = 0 and calculating an integrating factor, but this approach is incorrect. Instead, the correct method involves recognizing that the equation is separable and integrating both sides after rearranging the terms. The integrating factor method is not the appropriate technique for finding the solution in this case.

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fufufu
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Homework Statement


What is the general solution of tv' + v = 0?
book says it is v(t) = c/t but i don't see how
i tried to solve like this:

v' + (1/t)v = 0

p(t) = 1/t
P(t) = Ln(t)

y = e^ln(t) + c

= t + e^c

please help,thanks



Homework Equations





The Attempt at a Solution

 
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what is y?

your first equation is separable, write v'=dv/dt, then move all terms with a v to the LHS and all terms with a t to the RHS then integrate both sides
 
fufufu said:

Homework Statement


What is the general solution of tv' + v = 0?
book says it is v(t) = c/t but i don't see how
i tried to solve like this:

v' + (1/t)v = 0

p(t) = 1/t
P(t) = Ln(t)

y = e^ln(t) + c
This isn't right. What you're doing by calculating ##e^{\int p(t)\,dt}## is finding an integrating factor, not the solution to the differential equation. Check your textbook to see what you're supposed to do with this factor.

(Or solve the problem the way lanedance suggested.)
 

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