Easy exponential question-> 1/3(8)^(-2/3)

  • Thread starter Thread starter nukeman
  • Start date Start date
  • Tags Tags
    Exponential
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
nukeman
Messages
651
Reaction score
0
Easy exponential question---> 1/3(8)^(-2/3)

Homework Statement



I am doing a linear approximation question, and got stuck here with this simple stuff.

1/3(8)^(-2/3)

Can anyone explain what I need to do to turn the above into 1/12 ?



Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org


nukeman said:

Homework Statement



I am doing a linear approximation question, and got stuck here with this simple stuff.

1/3(8)^(-2/3)

Can anyone explain what I need to do to turn the above into 1/12 ?



Homework Equations





The Attempt at a Solution


$$8^{\frac{-2}{3}} = \frac{1}{8^{\frac{2}{3}}}$$
 


nukeman said:

Homework Statement



I am doing a linear approximation question, and got stuck here with this simple stuff.

1/3(8)^(-2/3)

Can anyone explain what I need to do to turn the above into 1/12 ?



Homework Equations





The Attempt at a Solution


What you have written reads as
[tex]\frac{1}{3} 8^{-2/3}.[/tex] Is that what you meant, or did you want
[tex]\frac{1}{3\, 8^{-2/3}}?[/tex]
If you mean the first one you should use brackets, like this: (1/3) 8^(-2/3), but if you mean the second one you should write 1/(8 2^(-2/3)).

RGV
 


As BloodyFrozen said, 8-2/3= 1/82/3. Further, since 23= 8, 81/3= 2 and so 82/3= 22= 4.