Easy interference problem regarding Newton's rings

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Homework Help Overview

The discussion revolves around an interference problem related to Newton's rings, focusing on phase shifts due to reflections and the conditions for dark rings in the interference pattern.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of phase shifts during reflections, questioning whether the phase shift is λ/2 or λ. There is an emphasis on understanding the conditions leading to dark rings and the role of thickness in the path difference.

Discussion Status

The discussion is active, with participants seeking clarification on the phase shifts involved and the specific conditions for the interference pattern. Some guidance has been offered regarding the nature of reflections and their impact on phase, but no consensus has been reached on the exact phase shift values.

Contextual Notes

Participants are considering the effects of different refractive indices and potential errors in their assumptions about phase shifts. There is an acknowledgment of the complexity involved in determining the correct phase shift for the problem at hand.

LCSphysicist
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Homework Statement
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Relevant Equations
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1596664909032.png

Unfortunately, i found r² = (R1)(R2)(λ)*(n-1/2)/(R1-R2)
1596665302749.png

I imagined a difference of phase λ/2 on the blue ray.
The grey is the air maybe polluted, as currently
 

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Please show us your work. Did you take into account any phase shifts due to reflections?
 
TSny said:
Please show us your work. Did you take into account any phase shifts due to reflections?
OOps
I thought that can the error is in the reflections yes.
1596670767713.png

t is the thickness, that is, the difference of path, but:

2t = (n-1/2)λ

where the half is the difference of phase.
 
To be more specific, the red ray will reflect first without change of phase, and a part of it will be transmitted.
In this transmission, it will suffer another reflection, but this case the difference of refraction indice will make a difference of phase λ/2 (here i am a little confused if is λ/2 or λ
 
LCSphysicist said:
To be more specific, the red ray will reflect first without change of phase, and a part of it will be transmitted.
In this transmission, it will suffer another reflection, but this case the difference of refraction indice will make a difference of phase λ/2 (here i am a little confused if is λ/2 or λ

If a reflection causes a phase shift, it will be a phase shift of ##\lambda/2##. Yes, there is a phase shift at the second reflection but not at the first reflection.

Keep in mind that you are dealing with the dark rings.
 
Last edited:

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