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Easy Motion Problem - Distance

  1. Mar 24, 2008 #1
    1. The problem statement, all variables and given/known data
    A Car Completes two laps of a 2.2 km racetrack is 98 seconds Find:
    A.) The Cars distance travelled (in km).


    2. Relevant equations+3. The attempt at a solution
    I know that you have to multiply 2.2km by 2 laps but for my homework i have to show a formula and complete a full answer
    (what am i given)
    [something] = 2 [meaning laps]
    [something] = 2.2 km
    [tex]\Delta[/tex]d = ?

    (required formula)
    [tex]\Delta[/tex]d = [something]*[something]
    [tex]\Delta[/tex]d = 2 * 2.2
    [tex]\Delta[/tex]d = 4.4 km

    (therefore statement)
    [therefore] the distance travelled by the runner would be 4.4 km



    I know what 2*2.2 is im not stupid but i don't know the correct formula to use and i don't know what symbols to fill in where the [somethings] are. Help?
     
  2. jcsd
  3. Mar 24, 2008 #2

    Kurdt

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    Strange question. There is no particular formula other than the distance is equal to the no. of laps multiplied by the distance per lap.
     
  4. Mar 24, 2008 #3
    Also if asked for the displacement of the object, it would be 0 due to the circular track you would end where you started correct? Is there a formula for displacement using the given information or what should i show to get 0 as displacement.
     
  5. Mar 24, 2008 #4

    Kurdt

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    You are correct that displacement would be zero but for this problem i don't think you'd have to show anything other than state that its zero.
     
  6. Mar 24, 2008 #5
    Mmm alright i'll have to ask my prof on wed. because it wants a forumla..mabey im supposed to just figure that out or something.
     
  7. Mar 24, 2008 #6

    Kurdt

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    There isn't really an equation you can give. You're just using your knowledge that the track starts and ends at the same point.
     
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