Easy proof don't know where i am going wrong

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The discussion centers around verifying the equation (1+i)^(95) = (1-i)*2^(47). The user initially miscalculated the expression, mistakenly arriving at (1+i)*2^(47) instead. The correct approach involves using the polar form of complex numbers, specifically z^(n) = r^(n) * e^(i*n*theta), and accurately determining the sine value for theta. The user corrected their error regarding sin(95π/4), realizing it should be -1/√2 instead of 1/√2.

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the question is show that (1+i)^(95) =(1-i)*2^(47)
we are told that z^(n) = r^(n) * e^(i*n*theta)

when i do the problem i get

(1+i)^(95) =(1+i)*2^(47)

can anybody verify whether i am right or wrong. thanks :biggrin:
 
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show me your r and theta b4 i can further help you... the question has no problem and I get (1-i)*2^47
 
stupid me... i know what it is now... my problem was that i had sin(95pi/4) = 1/sqrt2 and not the negative of that... thanks checking the problem

:approve:
 

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