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Mercury has a thermal expansion coefficient (volume) of about 1/5500 perKelvin. Estimate the inner diameter of the thermometer tube.

Here's my attempt.

L [tex]\approx[/tex] 30cm

V = 2*pi*r^2*L

Change in volume at 0 C and 110 C approximately equal to V

=> 110/5500 = r^2(3*pi/5)

=> r = sqrt(1/30*pi) [tex]\approx[/tex] 0.10m

I am well known to make crazy errors but I can't find out where that is over here

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# Homework Help: Easy question but I get a crazy answer

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