Easy way to get the expectation value of momentum squared?

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SUMMARY

The discussion centers on the relationship between momentum squared () and position squared () in the context of Gaussian distributions. The user seeks to express in terms of to simplify calculations. It is established that to obtain , one must apply the position-space operator twice. Additionally, the conversation touches on the classical relationship between

^2 and , indicating a deeper exploration of these concepts is necessary.

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  • Understanding of quantum mechanics principles, specifically momentum and position operators.
  • Familiarity with Gaussian distributions and their properties.
  • Knowledge of classical mechanics, particularly the relationships between momentum and position.
  • Basic mathematical skills for manipulating operators and equations.
NEXT STEPS
  • Research the application of position-space operators in quantum mechanics.
  • Study the mathematical properties of Gaussian distributions in physics.
  • Explore the classical and quantum relationships between momentum and position.
  • Learn about operator algebra in quantum mechanics for better manipulation of and .
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Students and professionals in physics, particularly those focused on quantum mechanics and mathematical physics, will benefit from this discussion.

chi-young
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Hello, I've been trying to define <p2> in terms of <x2>, much the same way that you can write <p> = m d<x>/dt, because it would be easier in my calculations.

Is this possible, or am I on a fools errand?

Edit: For Gaussian distributions.
 
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To get p^2 you apply the position-space operator twice.
What's the problem?

Oh you want the classical relation - so you'd need the relationship between <p>^2 and <p^2>?
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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