Edgar's Question from Facebook: Convex Polygon

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    Convex Polygon
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SUMMARY

The problem presented by Edgar involves finding the number of sides of a convex polygon where the sum of the interior angles is ten times the sum of the exterior angles. Utilizing the theorem that the sum of the interior angles for a convex polygon with \( n \) sides is \( S = (n-2)180^{\circ} \) and knowing that the sum of the exterior angles is always \( 360^{\circ} \), the equation \( (n-2)180^{\circ} = 10 \cdot 360^{\circ} \) leads to the solution \( n = 22 \). Therefore, a convex polygon with 22 sides satisfies the condition set forth in the problem.

PREREQUISITES
  • Understanding of convex polygons
  • Knowledge of the sum of interior angles theorem: \( S = (n-2)180^{\circ} \)
  • Familiarity with the concept that the sum of exterior angles is \( 360^{\circ} \)
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of convex polygons
  • Learn more about the relationship between interior and exterior angles
  • Explore other geometric theorems related to polygons
  • Practice solving problems involving polygon angle sums
USEFUL FOR

Students studying geometry, mathematics educators, and anyone interested in solving geometric problems involving polygons.

Sudharaka
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Edgar from Facebook writes:

The sum of the measures of the interior angles of a convex polygon is ten times the sum of the measures of its exterior angles. Find the number of sides of a polygon.

Hello could you please help me to solve this problem?
 
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Hello Edgar,

We need two theorems here:
  • For a convex polygon having $n$ sides, the sum $S$ of the interior angles is given by $S=(n-2)180^{\circ}$.
  • Regardless of the number of sides, the sum of the exterior angles is $360^{\circ}$.

Hence, we need to solve the following for $n$:

$(n-2)180^{\circ}=10\cdot360^{\circ}$

Divide through by $180^{\circ}$:

$(n-2)=10\cdot2$

$n-2=20$

$n=22$

Thus, we have found a convex polygon having 22 sides meets the stated requirement.
 

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