MHB Edgar's Question from Facebook: Convex Polygon

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    Convex Polygon
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The problem states that the sum of the interior angles of a convex polygon is ten times the sum of its exterior angles. The formula for the sum of the interior angles of a convex polygon with n sides is S=(n-2)180°. The sum of the exterior angles is always 360°. By setting up the equation (n-2)180°=10*360° and solving, it is determined that n=22. Therefore, a convex polygon with 22 sides satisfies the condition given.
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Edgar from Facebook writes:

The sum of the measures of the interior angles of a convex polygon is ten times the sum of the measures of its exterior angles. Find the number of sides of a polygon.

Hello could you please help me to solve this problem?
 
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Hello Edgar,

We need two theorems here:
  • For a convex polygon having $n$ sides, the sum $S$ of the interior angles is given by $S=(n-2)180^{\circ}$.
  • Regardless of the number of sides, the sum of the exterior angles is $360^{\circ}$.

Hence, we need to solve the following for $n$:

$(n-2)180^{\circ}=10\cdot360^{\circ}$

Divide through by $180^{\circ}$:

$(n-2)=10\cdot2$

$n-2=20$

$n=22$

Thus, we have found a convex polygon having 22 sides meets the stated requirement.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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