MHB Edgar's Question from Facebook: Convex Polygon

  • Thread starter Thread starter Sudharaka
  • Start date Start date
  • Tags Tags
    Convex Polygon
AI Thread Summary
The problem states that the sum of the interior angles of a convex polygon is ten times the sum of its exterior angles. The formula for the sum of the interior angles of a convex polygon with n sides is S=(n-2)180°. The sum of the exterior angles is always 360°. By setting up the equation (n-2)180°=10*360° and solving, it is determined that n=22. Therefore, a convex polygon with 22 sides satisfies the condition given.
Sudharaka
Gold Member
MHB
Messages
1,558
Reaction score
1
Edgar from Facebook writes:

The sum of the measures of the interior angles of a convex polygon is ten times the sum of the measures of its exterior angles. Find the number of sides of a polygon.

Hello could you please help me to solve this problem?
 
Mathematics news on Phys.org
Hello Edgar,

We need two theorems here:
  • For a convex polygon having $n$ sides, the sum $S$ of the interior angles is given by $S=(n-2)180^{\circ}$.
  • Regardless of the number of sides, the sum of the exterior angles is $360^{\circ}$.

Hence, we need to solve the following for $n$:

$(n-2)180^{\circ}=10\cdot360^{\circ}$

Divide through by $180^{\circ}$:

$(n-2)=10\cdot2$

$n-2=20$

$n=22$

Thus, we have found a convex polygon having 22 sides meets the stated requirement.
 
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...
Back
Top