Effect of a magnetic field on a bean of particles.

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The discussion focuses on determining how a magnetic field affects a beam of charged particles emitted at a small angle relative to the field. The key equation involves the force on the particles, F = q(v x B), and the resulting motion described by dv/dt = -q/m B x v. The challenge arises from the beam being nearly parallel to the magnetic field, which complicates the calculation of the cross product. To solve the problem, it is suggested to analyze the outer edge of the beam by introducing a small angle approximation and calculating the trajectory of particles over time. Ultimately, the goal is to show that the magnetic field focuses the beam to a point at a specific distance related to the beam's velocity and charge.
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Homework Statement


a beam of particles of charge q with velocity v is emitted from a point source, roughly parallel with a magnetic field B, but with a small angle of angular dispersion. Show that the effect of the field is to focus the beam to a point at a distance z = 2[/pi]mv/|q|B.


Homework Equations


We know the force F= q vxB
dv/dt = -q/m Bxv


The Attempt at a Solution


I try to solve the problem with the force. However, since the beam is roughly parallel to B, the cross product tends to 0. I am now like clueless...
 
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The initial velocity is approximately parallel to B, not exactly parallel. Try calling the angle between v and B, \theta and calculating r(t) for a particle on the beams outer edge. Then use a Taylor approximation for your expression for small \theta to find the location where r(t) lies on the z-axis (assume that B points in the z-direction).
 
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