Effective reisistance of an unbalanced wheatstone bridge.

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Homework Help Overview

The discussion revolves around determining the effective resistance of an unbalanced Wheatstone bridge, specifically with given resistor values. The original poster expresses difficulty in finding a method to approach the problem.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Some participants suggest using Kirchhoff's Current Law (KCL) to find node voltages, assuming a voltage across the bridge. Others inquire for further clarification on the method proposed.

Discussion Status

Participants are exploring the node voltage method as a potential approach, with some expressing a need for more detailed explanations. There is no explicit consensus on the method yet, but guidance has been offered regarding the use of KCL.

Contextual Notes

The original poster is preparing for an exam and seeks a straightforward method to solve the problem, indicating a time constraint. The specific resistor values are provided, highlighting the unbalanced nature of the bridge.

Mr Virtual
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Homework Statement



I have an exam and therefore quick help is requested.

I need a simple way to find out the resistance of an unbalanced wheatstone bridge.
Suppos R1=2 ohm, R2=1 ohm, R3=4 ohm, R4=4 ohm and the connecting bridge's R5=10 ohm.
Here, R1/R2 is not equal to R3/R4. Then How to find net resistance.


The Attempt at a Solution



I don't know and can't find any way to attempt such a question, though there must be many. So no idea how to do this.

Help please!


Mr V
 
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Usually on problems like this one, you can use KCL to solve for the node voltages (assume 1V across the whole bridge for the calculation). Once you have the node voltages, those give you the currents, which gives you the total current for the 1V excitation, which gives you the resistance.
 
A little more explanation?
 
Mr Virtual said:
A little more explanation?

I agree with berkeman. Use the node voltage method, for the two nodes on either side of R5.

You'll have 2 equations, with two unknowns. Once you have the voltage of those two nodes, you can get the current coming out of the voltage source in terms of V.

Then resistance is just V/I.
 
Thanks so much!
 

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