- #1

User1265

- 29

- 1

- Homework Statement
- My Question is how would find the current of the ammeter

Image inserted in solution

The answer says "balanced wheatstone bridge, I = 0" I do not quite understand.

- Relevant Equations
- V=IR

I tried to solve by making 4 ohm and 8 ohm, which I believe are parallel as one effective resistance, and making 6 and 12 ohms which I believe are parallel as one effective resistance, and diving the total of the two effective resistance by the total voltage, but by doing so, I can only find the total current in the circuit, whereas I need the current in the branch containing the ammeter.

However the answer noted it was a 'balanced wheatstone bridge'. What does this mean? and what are the implications of this upon solving to find the current in the Ammeter?

However the answer noted it was a 'balanced wheatstone bridge'. What does this mean? and what are the implications of this upon solving to find the current in the Ammeter?