Determine the unknown resistance using a Wheatstone Bridge.
Unknown Resistance = known resistance (100-Length) / Length
The Attempt at a Solution
I've connected the set up as shown in the pictures but my only concern is, I don't have a resistance box so I'm using those blue boxes which seem like a resistance box to me but with just one resistance instead of many. I connected the wire of unknown resistance as shown, I stripped off the insulation of the copper wire and then wrapped it around. The null point I'm getting it not in the middle, it's closer to the higher potential and I get the resistance of the wire to be approximately 2.2 ohms when I use the 10 ohm blue resistance box. Is that correct?
Secondly, the circuit diagram provided to us also has a rheostat, what use is a rheostat in this experiment?