Efficient Integration: Substitution Method for 2x sec^2(x^2) dx

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rugapark
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the question is [tex]\int 2x sec^2 (x^2) dx[/tex]

do i sub u= sec (x^2) ?

I so far have got to trying to sub u= sec(x^2) and getting du= 2 (sec x^2 tan x^2)... i have a strong feeling i fudged the "du" part. hmm.
 
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[tex]u=x^2[/tex]

[tex]du=2xdx[/tex] which you have! What is the anti-derivative of [tex]\sec^2 x[/tex] ?
 
oh right, so I've got du=2xdx,

intergral sec^2 u du

= tan u + c

sub back u=x^2

=tan x^2 +c

how does that look?