Efficient U-Substitution for (x^2)(sinx)/(1+x^6)

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Homework Help Overview

The discussion revolves around an integration problem involving the expression (x^2)(sinx)/(1+x^6). Participants are exploring methods for simplifying or solving this expression, particularly through substitution techniques.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Some participants suggest using u-substitution, while others question the completeness of the original problem statement. There are also mentions of integration by parts as a potential approach.

Discussion Status

The discussion is ongoing, with various approaches being proposed. Some participants are questioning the assumptions made due to the lack of complete information from the original poster, while others are offering different perspectives on the substitution method.

Contextual Notes

There is a noted absence of complete problem details, which has led to varied interpretations of the task at hand. Participants express the need for more information to provide effective assistance.

nameVoid
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[ ( x^2 ) ( sinx ) ] / (1 + x^6)
 
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Cristo, I get 42. You might have forgotten to multiply by Hooker's constant (= 2.413793103).
 
Don't listen to these clowns. The answer you seek is

[ ( u^2 ) ( sinu ) ] / (1 + u^6)
 
jbunniii said:
Don't listen to these clowns. The answer you seek is

[ ( u^2 ) ( sinu ) ] / (1 + u^6)

That's an extremely useful substitution in those cases where you find the given variable esthetically displeasing for some reason.

For all other cases, not so much.
 
nameVoid,
If you're still out there, you would have gotten more serious (and helpful) responses if you had given us the complete problem. We can infer that this is an integration problem, although there was no indication of that in what you wrote. Also, if you want help, show us what you've tried.

The integral looks to me like it could be done using integration by parts in this way:
u = cos x
[tex]dv = \frac{x^2 dx}{1 + x^6}[/tex]

To find v, you'll have to integrate dv, which involves a substitution w = x3, dw = 3x2dx. I haven't worked it out, but this is what I would try first.
 

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