Efficiently Calculate Stopping Time for a Cyclist | Displacement Homework

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SUMMARY

The discussion focuses on calculating the stopping time for a cyclist who decelerates from 3.0 m/s to 0 m/s after applying brakes. The deceleration was determined to be -3.2 m/s². Using the equation V2 = V1 + (a)(t), the time required to stop from 3.0 m/s was calculated to be 0.9375 seconds. This method is confirmed as correct for determining the stopping time based on the established deceleration.

PREREQUISITES
  • Understanding of kinematic equations, specifically V2 = V1 + (a)(t)
  • Basic knowledge of acceleration and deceleration concepts
  • Familiarity with units of measurement in physics (m/s, m/s²)
  • Ability to perform algebraic manipulations to solve for time
NEXT STEPS
  • Review kinematic equations for uniformly accelerated motion
  • Explore real-world applications of deceleration in cycling and vehicle dynamics
  • Learn about the effects of friction and braking force on stopping distances
  • Investigate the relationship between speed, stopping time, and distance
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as educators looking for practical examples of motion and deceleration calculations.

chuckset
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Homework Statement


A cyclist is traveling with a speed of 11.0 m/s when she applies the brakes. After slowing for 2.5s, her speed has been reduced to 3.0 m/s. If she continues braking, how much longer will it take her to stop?

I found the deceleration to be -3.2 m/s^2
V1 = 3.0 m/s
V2 = 0

2. The attempt at a solution

I used the equation V2 = V1 + (a)(t) and got the change in time to be 0.9375s

Does this seem like the correct way to solve this?
 
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Well you found her deceleration correctly, so now what you want to get is the time it takes the cyclist to go from 11 m/s to 0 m/s.
 

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