Efficiently Solve Motion Problems Using Energy Conservation

Click For Summary
SUMMARY

The discussion focuses on solving motion problems using energy conservation principles. The participant encountered difficulties applying the formula d=V(i)t + 1/2at^2, while achieving correct results with Vf^2=Vi^2 + 2ad. The initial velocity was given as V(i)=8.9 m/s, and the vertical component of velocity was Viy=4.9 m/s at an angle of 35 degrees. The conversation emphasizes the importance of selecting appropriate formulas based on the problem's context and the values provided.

PREREQUISITES
  • Understanding of kinematic equations for constant acceleration
  • Familiarity with energy conservation principles in physics
  • Basic knowledge of projectile motion
  • Ability to resolve vector components, specifically for angles
NEXT STEPS
  • Study the derivation and application of kinematic equations in motion problems
  • Learn about energy conservation and its application in solving motion problems
  • Explore projectile motion concepts, focusing on vertical and horizontal components
  • Practice solving problems involving different angles and initial velocities
USEFUL FOR

Students studying physics, educators teaching motion concepts, and anyone interested in mastering energy conservation techniques in problem-solving.

majormuss
Messages
124
Reaction score
4

Homework Statement


I just came across this question and i think its giving me a real hard time.
This is part of a bigger question so I'll provide the other statements below
7 The maximum height reached by the ball is
approximately
(1) 1.2 m (3) 4.9 m
(2) 2.5 m (4) 8.5 m

Homework Equations


t=1 s and therefore half way is 0.50s
V(i)=8.9m/s
angle is 35 degrees
Viy= 4.9m/s

The Attempt at a Solution


First of all, why is it that I can't use certain formulas in Solving some motion problems even though everything seems to work ok. I tried using this formula...d=V(i)t +1/2at^2... but my answer turns out wrong. and this one rather gives me the answer...Vf^2=Vi^2 + 2ad...why is that?
 
Last edited by a moderator:
Physics news on Phys.org


Since you know the initial velocity, why not try to solve it using energy conservation?
 
Hi majormuss! :smile:

(try using the X2 tag just above the Reply box :wink:)
majormuss said:
t=1 s and therefore half way is 0.50s

Viy= 4.9m/s

First of all, why is it that I can't use certain formulas in Solving some motion problems even though everything seems to work ok. I tried using this formula...d=V(i)t +1/2at^2... but my answer turns out wrong. and this one rather gives me the answer...Vf^2=Vi^2 + 2ad...why is that?

All the standard constant acceleration formulas will work. :wink:

I expect you got t = 0.5 s wrong … where did that come from?
 

Similar threads

  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
15
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 12 ·
Replies
12
Views
1K
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
993
Replies
28
Views
2K