Eigenvalues and Eigenvectors - Find x2(1)

  • Thread starter dvep
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  • #1
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Homework Statement




http://i1225.photobucket.com/albums/ee382/jon_jon_19/Eigen.jpg


The Attempt at a Solution



It is a bit too long to type it all out, but I was wondering whether I am correct:

I got,

A = 7/2 , B = 0 , C = -1/8 , D = 1/8

And from this I worked out, x2(1) = -1.03

Is this correct? I have been through and cannot find any faults in my working.

thank you.
 

Answers and Replies

  • #2
fzero
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It's correct. though it's possible that they want an exact expression instead of a numerical approximation.
 
  • #3
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It's correct. though it's possible that they want an exact expression instead of a numerical approximation.

thank you for your reply, that is good to hear.

Could you also check this one http://i1225.photobucket.com/albums/ee382/jon_jon_19/Eigen2.jpg

The second term should be De^( - √(5)t), I made a mistake when writing out the question.

Just want to make sure i got a good grasp of this, my answer is 3.09

thank you
 
  • #4
fzero
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