What are the eigenvalues and eigenvectors of the given matrix transformation?

[rmiller70015]

Homework Statement

<br /> \frac{d\vec{Y}}{dt}<br /> =<br /> \begin{bmatrix}<br /> 2 &amp; 4 \\<br /> 3 &amp; 6<br /> \end{bmatrix}<br /> \vec{Y}
Find the eigenvalues and eigenvectors

Homework Equations

The Attempt at a Solution

I found the eigenvectors to be
<br /> \vec{v_1} = <br /> \begin{bmatrix} <br /> 2 \\ <br /> 1 <br /> \end{bmatrix}<br /> ,<br /> \vec{v_2} = <br /> \begin{bmatrix}<br /> 2 \\<br /> -3 <br /> \end{bmatrix}<br />

I found a widget on Wolfram Alpha that says the second eigenvector should be:
<br /> \begin{bmatrix}<br /> 2 \\<br /> 3<br /> \end{bmatrix}<br />

I am more inclined to believe wolfram alpha is correct, but can someone show me why?

 

[pasmith]

How are we to determine whether, and if so how, you have made an error if you don't post your working?

 

[rmiller70015]

It was mostly by looking at the matrix and trying to make them the same and now that you say that when I do the algebra on it to post it, I see what I did wrong. I just tried to look at 3 and -2 to find the solution when I should have said 3x-2y=0 and 3x=2y then the vector becomes clear.

 

[Ray Vickson]

It was mostly by looking at the matrix and trying to make them the same and now that you say that when I do the algebra on it to post it, I see what I did wrong. I just tried to look at 3 and -2 to find the solution when I should have said 3x-2y=0 and 3x=2y then the vector becomes clear.

Neither of your $v_1$ or $v_2$ are eigenvectors. If $A$ is your matrix we have $Av_1 = (8,12)^T$, which cannot be a multiple of $v_1$: the first component of $v_1$ is larger than the second component, while the opposite is true for $Av_1$. Similarly, $v_2$ cannot be an eigenvector of $A$ because the components of $v_2$ have opposite signs, while those of $Av_2$ have the same sign.

Also: you did not show the eigenvalues.

 

[rmiller70015]

Eigens are 0,8. The problem was v2 I ommited a negative sign in the first vector on accident.

 

[Ray Vickson]

Eigens are 0,8. The problem was v2 I ommited a negative sign in the first vector on accident.

I do not understand what you are trying to say. What is the correct $v_1$? What is the correct $v_2$? Instead of trying to describe these in words, just show the actual numerical entries.

 

[rmiller70015]

<br /> \vec{v_1}=<br /> \begin{bmatrix}<br /> -2 \\<br /> 1<br /> \end{bmatrix}<br /> ,<br /> \vec{v_2}=<br /> \begin{bmatrix}<br /> 2 \\<br /> 3<br /> \end{bmatrix}<br />

Sory for putting so little work into this, I've got the answer and moved onto the next problem at this point.