Eigenvalues and eigenvectors of symmetric 2x2 matrix?

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Discussion Overview

The discussion revolves around the properties of eigenvalues and eigenvectors of symmetric 2x2 matrices, specifically addressing claims about the relationship between eigenvalues, the trace, and the determinant of such matrices. Participants explore theoretical aspects and examples related to diagonalization.

Discussion Character

  • Technical explanation, Debate/contested

Main Points Raised

  • One participant recalls a lemma suggesting that a 2x2 symmetric matrix can be diagonalized such that its eigenvalues are the trace and 0.
  • Another participant asserts that a general 2x2 symmetric matrix will not have an eigenvalue of 0, emphasizing that the trace equals the sum of its eigenvalues.
  • A similar point is reiterated by another participant, who also expresses uncertainty about the original claim.
  • It is noted that the eigenvalues of any symmetric matrix are real, but no special properties are attributed specifically to 2x2 symmetric matrices.
  • One participant states that the eigenvalues of a 2x2 matrix will be its trace and 0 only if the determinant of the matrix is zero.
  • A later reply challenges the initial claim by providing an example of a diagonalized identity matrix, which does not conform to the proposed eigenvalue structure.

Areas of Agreement / Disagreement

Participants express disagreement regarding the existence of an eigenvalue of 0 for general 2x2 symmetric matrices, with multiple competing views on the implications of the trace and determinant.

Contextual Notes

Some statements depend on the definitions of eigenvalues and the conditions under which matrices are diagonalized. The discussion does not resolve the implications of the determinant on the eigenvalues.

malawi_glenn
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Hello

I recall, I think, that there is a lemma which states that a 2x2 symmetric matrix can be diagonalized so that its eigenvalues are (trace) and 0.

I can not find it anywhere =/ I think it was a physics teacher who told us this a couple of years ago, can anyone enlighten me?

cheers
 
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A general 2x2 symmetric matrix will not have an eigenvalue 0. The trace of a symmetric 2x2 matrix is equal to the sum of it's eigenvalues, maybe that was what you were thinkig of?
 
Last edited:
dx said:
A general 2x2 symmetric matrix will not have an eigenvalue 0. The trace of a symmetric 2x2 matrix is equal to the sum of it's eigenvalues, maybe that was what you were thinkig of?

hmm yeah, maybe something like that.

Thanx for input
 
The trace of a matrix is always equal to the sum of it's eigenvalues. I don't think there is anything special about the eigenvalues of a 2x2 symmetric matrix, but eigen values of any symmetric matrix will be real (non-imaginary).
 
The eigenvalues of any 2x2 matrix will be its trace and 0 if and only if the determinant of the matrix vanishes
 
<<I recall, I think, that there is a lemma which states that a 2x2 symmetric matrix can be diagonalized so that its eigenvalues are (trace) and 0>>

We can see that is not true by considering a trivial example of a matrix that already is diagonalized.

For example, if you digonalize an identity matrix, you get back the identity matrix. It, of course, does not have (trace) and zero as the diagonal elements.
 

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