Eigenvalues of Linear Time Varying systems

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SUMMARY

The discussion focuses on the limitations of using traditional eigenvalues for stability analysis in Linear Time Varying (LTV) systems. It highlights that while frozen eigenvalues may indicate stability, they do not capture the dynamic behavior of states in LTV systems. The example provided illustrates that for a simple drag system, the eigenvalue remains negative, indicating stability, but emphasizes the need to analyze state interactions for a comprehensive understanding of LTV stability.

PREREQUISITES
  • Understanding of Linear Time Varying (LTV) systems
  • Familiarity with eigenvalue analysis in control systems
  • Knowledge of state-space representation
  • Basic principles of stability in dynamical systems
NEXT STEPS
  • Research the concept of dynamic state interactions in LTV systems
  • Explore advanced stability criteria for LTV systems
  • Learn about Lyapunov stability methods for time-varying systems
  • Investigate the role of eigenvalue derivatives in stability analysis
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Control engineers, systems analysts, and researchers focusing on stability analysis in Linear Time Varying systems.

sodemus
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The usual eigenvalues of a LTV system does not say much about the stability but my intuition tells me there should be some kind of extension that applies to LTV systems as well. Like including some kind of inner derivative of the eigenvalues or something, I don't know...

I guess in some way part of my question is something like, what invalidates the 'frozen' eigenvalues as a stability analysis tool for LTV systems? What is overlooked?

I can understand that my question can appear a bit fuzzy so please try ask follow-ups!
 
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Hard to say for a non-linear LTV in general, but if you consider the simple example of v^2 drag [Vdot = -k/2*V*abs(V)], then you can write the state matrix for a given velocity as...

dVdot = -k/2(abs(V0)+V0*sign(V0))*dV

For V0 > 0 dVdot = -k*V0*dV
For V0 < 0 dVdot = -k*abs(V0)*dV

For this system its very simple to see that for any V0, the eigenvalue is always going to be a negative value with magnitude -k*V0. The pole of this system is neutrally stable when V0 = 0, but it otherwise always located in the stable left half plane.

For an LTV, we simply replace V0 with V, and the same relationship holds. You need to investigate the dynamic behavior of the states as well as their interactions with one another if you want to ensure and LTV system is stable.
 

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