Eigenvalues of the Frenet formulas and angular velocity

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SUMMARY

The discussion centers on the eigenvalues of the curvature matrix K derived from the Frenet-Serret formulas for a circular helix defined by the parametric equations \(\vec x(t)=(a\cos(\alpha t), a\sin(\alpha t), bt)\). It is established that the nonzero eigenvalue of \(K^2\) is \(-\alpha^2\). Participants clarify that this conclusion can be drawn from the properties of the curvature matrix without direct computation, leveraging theoretical insights from differential geometry.

PREREQUISITES
  • Understanding of Frenet-Serret formulas
  • Knowledge of eigenvalues and eigenvectors in linear algebra
  • Familiarity with parametric equations of curves
  • Basic concepts of differential geometry
NEXT STEPS
  • Study the derivation of the Frenet-Serret formulas in detail
  • Learn how to compute eigenvalues of matrices, specifically for curvature matrices
  • Explore the geometric interpretation of eigenvalues in the context of curves
  • Investigate the properties of circular helices and their applications in physics
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Mathematicians, physicists, and students studying differential geometry or vector calculus, particularly those interested in the properties of curves and their curvature matrices.

ForMyThunder
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So there's a circular helix parametrized by \vec x(t)=(a\cos(\alpha t), a\sin(\alpha t), bt) and you have the matrix K given in the Frenet-Serret formulas. In the book I'm reading it says that -\alpha^2 is the nonzero eigenvalue of K^2. Can someone explain how they know this is? I understand that you can compute the eigenvalues of the matrix to verify this but how can you say this without computation?
 
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ForMyThunder said:
So there's a circular helix parametrized by \vec x(t)=(a\cos(\alpha t), a\sin(\alpha t), bt) and you have the matrix K given in the Frenet-Serret formulas. In the book I'm reading it says that -\alpha^2 is the nonzero eigenvalue of K^2. Can someone explain how they know this is? I understand that you can compute the eigenvalues of the matrix to verify this but how can you say this without computation?

Can you show me why the eigen value is -alpha^2?

I get +-alpha^2/(a.alpha^2 + b^2)
 

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