Einstein's Equation: Calculate Frequency of Proton

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Homework Help Overview

The problem involves calculating the frequency associated with a proton's kinetic energy in the context of Einstein's equation, which is typically related to photoelectric effects. The original poster presents values for kinetic energy and work function, along with constants for conversion.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of Einstein's equation, questioning the relevance of protons in the context of photoelectric emission, which traditionally involves photons and electrons. There is also a discussion about the correct interpretation of the variables and constants involved in the equation.

Discussion Status

There is ongoing clarification regarding the original problem statement, with some participants suggesting that 'proton' may be a typo for 'photon'. The discussion includes attempts to reformulate the equation for frequency based on the provided kinetic energy and work function.

Contextual Notes

Participants note potential typos in the problem statement and question the appropriateness of the terms used, indicating a need for clearer definitions and context for the variables involved.

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Homework Statement


Calculte the frequency of the proton with a kinetic energy of 1.97*10-16ev if the work function of the metal is 1.33*10-16
(IeV=1.6*10-19J, h=6.60*10-34Js



Homework Equations



E = hf-hfo=hf-Wo

Where E= maximum kinetic energy

h= Plancks's constant
Wo=hfo=work function

f=frequency of the incidented light

The Attempt at a Solution



from E = hf-Wo, we have

f = E+Wo/h
f = 1.97*10-16+1.33*10-16/6.60*10-34

What about the IeV=1.6*10-19J?

Where can I subtitute that one into?
 
Last edited:
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The problem's statement does not make sense. Einstein's equation, which is presumably the one dealing with photoelectric emission, is about electrons and photons, not protons.

What is really given and what is required to determine?
 
voko said:
The problem's statement does not make sense. Einstein's equation, which is presumably the one dealing with photoelectric emission, is about electrons and photons, not protons.

What is really given and what is required to determine?

The problem says:

Calculte the frequency of the proton with a kinetic energy of 1.97*10-16ev if the work function of the metal is 1.33*10-16
(IeV=1.6*10-19J, h=6.60*10-34Js
 
chikis said:
Calculte the frequency of the proton with a kinetic energy of 1.97*10-16ev if the work function of the metal is 1.33*10-16
Fairly clearly 'proton' is a typo for 'photon'
(IeV=1.6*10-19J, h=6.60*10-34Js
Another typo: should be '1ev'
from E = hf-Wo, we have
f = E+Wo/h
I hope you mean f = (E+Wo)/h
 
haruspex said:
Fairly clearly 'proton' is a typo for 'photon'

Another typo: should be '1ev'

I hope you mean f = (E+Wo)/h

Yes!
 

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