Elastic Collision between projectile and a pendulum, what's the initial speed?

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Homework Help Overview

The problem involves an elastic collision between a projectile and a pendulum. A 29.0 g ball is fired horizontally towards a 100 g ball hanging from a string, and the scenario requires determining the initial speed of the projectile based on the resulting motion of the pendulum after the collision.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of conservation of momentum and energy principles, questioning the use of mass ratios in elastic versus inelastic collisions. There are attempts to derive expressions for the initial speed of the projectile based on the final velocity of the pendulum and the angle of swing.

Discussion Status

Multiple participants are exploring different calculations and interpretations of the problem. Some have provided their calculations and reasoning, while others are questioning the correctness of specific steps or assumptions made in the derivations. There is no explicit consensus on the correct approach or final answer yet.

Contextual Notes

Participants note the importance of using the correct equations for elastic collisions and the implications of mass ratios in their calculations. There is also mention of the difficulty in typing out complex algebraic expressions, which may affect clarity in communication.

Fromaginator
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Homework Statement


A 29.0 g ball is fired horizontally with initial speed v0 toward a 100 g ball that is hanging motionless from a 1.10 m-long string. The balls undergo a head-on, perfectly elastic collision, after which the 100 g ball swings out to a maximum angle θmax = 50.0°
see image for question

Homework Equations


Ki + Ui = Kf + Uf
vp = √[2*g*L*(1 - cosθ)]
mb*v0 = mp*vp + mb*vb



The Attempt at a Solution


I suspect you have to use the mass ratio and it's relation to the ratio of momentum or kinetic energy, but I have been unsuccessful in getting the correct answer. The tried answers are availible along with the question in the image.
 

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I got a different answer. But I can't just tell you - that would be spoiling your learning. If you show your calculation, I can suggest improvements.
 
I think the problem with my calculations was that I used a mass ratio which I think only applies to inelastic but here's what I did
0.5*mp*vp² = mp*g*L*(1 - cosθ)

vp = √[2*g*L*(1 - cosθ)]

0.5*mb*v0² = 0.5*mb*vb² + 0.5*mp*vp²
mb*v0² = mb*vb² + mp*vp²
mb*vb² = mb*v0² - mp*vp²
vb = √[v0² - (mp/mb)*vp²]

v0 = √[v0² - (mp/mb)*vp²] + (mb/mp)*vp


mb = 27 g
mp = 100 g
vp = √[2*g*L*(1 - cosθ)]; L = 1.1 m, θ = 50º

vp = 2.775 m/s

mp/mb = 3.70

v0 = √[v0² - (3.7)*7.701] + (3.7)*2.775
v0 = √[v0² - 28.5] + 10.27
v0 - 10.27 = √[v0² - 28.5]
v0² - 20.54*v0 + 105.4 = v0² - 28.5
- 20.54*v0 + 105.4 = - 28.5

v0 = 6.52 m/s

I'm pretty sure the vp(final velocity of the pendulum is right)
 
Fromaginator said:
v0 = √[v0² - (mp/mb)*vp²] + (mb/mp)*vp

This came from the conservation of momentum equation, but you made a mistake here. If you write out the full momentum equation, you'll see what it should be.
 
I got it!
vp=[2mb/(mb+mp)]*vb
0.5*mvbf^2+mghf=0.5*mvbi^2+mghi
gL(1-costheta)=).5(Vo^2)(3364/16641)
Vo=6.17m/s

although when I actually did it there were a few more intermeadiate steps but I didn't feel it necessary to type out the algebra since square roots and fractions are hard to type.
 

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