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Elastic Collision problem with atoms.

  1. Jan 11, 2009 #1
    1. The problem statement, all variables and given/known data

    A neutron in a nuclear reactor makes an elastic head-on collision with the nucleus of a carbon atom initially at rest.

    (a) What fraction of the neutron's kinetic energy is transferred to the carbon nucleus? (The mass of the carbon nucleus is about 12 times the mass of the neutron.)




    2. Relevant equations

    Conservation of momentum: M1V1i+M2V2i=M1V1f+M2V2F
    Conservation of Kinetic Energy: 1/2M1V1i^2+1/2M2V2i^2=1/2M1V1F^2+1/2M2V2F^2



    3. The attempt at a solution


    Since V2i=0
    M1V1i=M1V1F+M2V2F

    and

    1/2M1V1i^2=1/2M1V1F^2+1/2M2V2F^2 <--- 3 unknowns V1i,V1F,V2F so i need 3 equations to solve for them.

    (1)(V1i)=(1)(V1F)+(12)(V2F)
    V2F=V1i-V1F/12

    umm so i was wondering if im on the right track to solving this problem?
     
  2. jcsd
  3. Jan 11, 2009 #2
    You are on the right track. Since V2i = 0 and using the conservation of momentum and kinetic energy equations one gets

    V1F = ((M1 - M2)/(M1 + M2))V1i

    V2F = (2M1/(M1 + M2))V1i

    You arrive at these equations by rearranging the momentum and energy equations by grouping the initial and final velocities of the first mass on one side of the equation and doing the same on the other side for the second mass. Then divide the rearrange energy equation by the rearranged momentum equation using the difference of two perfect squares factoring i.e. a2 - b2 = (a + b)(a - b). This gives

    V1i - V2i = V2F - V1F

    Using the above equation and the rearranged momentum equation the final velocities can be obtained.
     
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