Elastic Collision: Who Experiences Larger Accel?

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In an elastic collision between a cart of mass M and another of mass 2M, the carts experience different magnitudes of acceleration due to their differing masses. Newton's second law indicates that the same force acting on the two carts results in different accelerations, with the heavier cart (2M) experiencing less acceleration than the lighter cart (M). The discussion emphasizes the importance of applying conservation of momentum and Newton's laws to analyze the situation correctly. It clarifies that the forces exerted during the collision are equal and opposite, leading to the conclusion that the lighter cart experiences a larger magnitude of acceleration. Understanding these principles is crucial for solving problems related to elastic collisions.
justagirl
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A cart of mass M and a second cart of mass 2M collide head on elastically and bounce apart. Which cart experiences a larger magnitude of acceleration during the collision?
 
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I think the strategy for this question may be as simple as: think Newton's second law
 
apply conservation of momentum.
m1v1 = m2v2, assuming they are traveling at the same velocities.

you derive then for the acceleration. (algebraically speaking)
James
 
?

I'm not sure what you're getting at here...there is no reason to assume that they are traveling at the same velocity, and even if they were, why should the momentum of the first cart equal that of the second? Conservation of momentum states that the TOTAL momentum of the system should be the same before and after the collision. So, using primed quantities to represent values after the collision:

m1v1 + m2v2 = m1'v1' + m2'v2'

In any case, I don't see how that helps her answer the problem. Using Newton's third law, the two carts exert equal and opposite contact forces on each other. By Newton's second law, the same force accelerates two different masses by different amounts, and it imparts a cart twice as heavy with half the acceleration, right?
 
Touche!~ I now remember a tennis ball and basketball demonstration. Yes it is the action/reaction forces at play here. Forget what I said before.

Duh!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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