Elastic collison of 2 moving object

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The discussion focuses on solving a perfectly elastic collision problem involving two objects: a 0.900 kg object moving east at 2.8 m/s and a 1.30 kg object moving west at 1.4 m/s. The conservation of momentum and kinetic energy equations are established as m1V1i + m2V2i = m1V1f + m2V2f and m1V1i^2 + m2V2i^2 = m1V1f^2 + m2V2f^2. The user is guided to substitute the given values into these equations and to consider the direction of motion when calculating the final velocities after the collision.

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a .900 kg object is moving east at 2.8 m/s.
a 1.30 kg object is moving west at 1.4 m/s.
If the collision is perfectly elastic find the velocities after the collision. (neglect friction)

I know momentum and kinetic energy is conserved but I am really clueless as to what to do.
Please help me start this problem.
 
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Two simultaneous equations here may be useful, one for KE and one for momentum.

Let V1i be object 1's velocity before impact V2i be object 2's veloctiy before impact V1f be object 1's velocity after imapct and V2f be object 2's velocity after impact. m1 is first object's mass, m2 = object 2's mass

Then m1V1i + m2V2i = m1V1f + m2V2f.
m1V1i^2 + m2V2i^2 = m1V1f^2 + m2V2f^2

(Note how I have canceled out the 'half' in K = 1/2 * mv^2 - in effect doubling every term in the 2nd equation, so it's simpler to work with but still doesn't effect the system of equations).

Substitute in the values you are given. Take moving east as moving in the positive direction (and therefore moving west in the negative direction).
 
You can just use Vi - Vf = -(V2i - V2f)

Is a shortcut my professor showed us instead of using quadratics by 1/2 mv^2
 

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