Solving an Elastic Collision Problem with Given Force-Time Data

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The discussion revolves around solving an elastic collision problem involving a 10-kg mass colliding with a 2-kg mass, with provided force-time data. The impulse calculated from the force-time chart is 20 N*s, leading to an initial velocity of 2 m/s for the 10-kg mass. The user attempts to apply conservation of momentum and energy equations to find the final velocities of both masses but encounters discrepancies in the momentum conservation calculations. The final results for the initial and final velocities are questioned, particularly how the initial velocity of 6 m/s was derived. The conversation highlights the challenges in applying impulse and conservation principles correctly in elastic collision scenarios.
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Homework Statement



A 10-kg mass moving at a speed of V_{1} in a positive direction collides elastically with a 2-kg mass which is initially at rest. The magnitude of the net force that acts on each object during the collision is shown in the figure. Find the initial velocity, V_{1}, of the 10-kg mass prior to collision, the final velocity, v_{3}, of the 10-kg mass, and the final velocity, v_{4}, of the 2-kg mass.

I can't post the figure up, but it's a force with respect to time chart. It starts with nothing, then starts to spike upwards at a constant rate from time 1 millisecond to time 3 milliseconds, where it peaks at 10000N, then goes back down at the same rate, hitting 0N at 5 milliseconds. I've already figured the Impulse is 20 N*s from this.

Homework Equations



p = mv

I = F/deltaT

/deltap = mv_{final} - mv_{initial}

mv_{before collision} = the some of mv_{after collision}

Possibly assorted others.

The Attempt at a Solution



So far, I know the Impulse is 20 NS.

Impulse = Momentum, I do believe.

So

20 = (10)V

Making Velocity of the first object initially = 2 m/s, correct?

That would answer the first question, but I'm not totally sure where to go from there.
 
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Here's a quick idea of what I tried to do...lemme know if it looks right.

20 = (10)V_{3} + 2(V_{4})
20 = .5(10)V_{3}^{2} + .5(2)V_{4}^{2}

Those are the conservation of momentum and energy equations.

I solved the momentum one for V_{3} and got .55279 m/s. I can post steps if anyone wants to see.

Then I plugged that into the energy one and got 1.7061 m/s. Sound about right?

It looks like it MIGHT be accurate, but the sums of mv before and the sums of mv after aren't equal.

I got 2(10) = 20 for before and 10(.55279) + 2(1.7061) = 8.94 for after. =/
 
Last edited:
my answers:

v1 + V3 = 10
2V1 = 12
V1 = 6 m/s
V3 = 4 m/s
 
How is V1 6m/s?

Am I doing the impulse equation wrong?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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