Elastic energy, spring equation. Help?

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SUMMARY

The discussion centers on calculating the height a 293g block reaches when launched from a spring with a spring constant of 161 N/m, compressed by 42 cm. The correct approach involves using the spring potential energy equation, Eel = 1/2 * k * x², to determine the energy stored in the spring, which then converts to gravitational potential energy, Eg = mgh. The user initially misapplied the equations but was corrected to properly equate the spring energy to the gravitational energy to find the height.

PREREQUISITES
  • Understanding of spring potential energy (Eel = 1/2 * k * x²)
  • Knowledge of gravitational potential energy (Eg = mgh)
  • Basic algebra for solving equations
  • Familiarity with unit conversions (grams to kilograms)
NEXT STEPS
  • Review the principles of energy conservation in mechanical systems
  • Practice problems involving spring constants and energy transformations
  • Explore the effects of varying mass and spring constants on launch height
  • Learn about real-world applications of springs in mechanics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy transformations, as well as educators looking for examples of spring energy calculations.

mrphobio
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Homework Statement


A 293g block is placed on a spring with a spring constant of 161N/m, compressing it 42cm. What height does the block reach when it is launched?

Homework Equations


Eel=1/2*k*x2
Eg=mgh

The Attempt at a Solution


Eg=.293*10*.42=1.2306

1.2306=1/2*161*x2
1.2306=80.5x2
.0153=x2
.1236=x

Did I make any mistakes? Because I can't get it right.

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nevermind i got it..
 
Last edited:
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Hi mrphobio,
You're using the equations the wrong way round.
The energy stored in the spring (0.5kx2) with spring constant k and compression of the spring x.

Since energy can't be destroyed, it is transformed into kinetic energy, and finally into potential energy (mgh) with mass m and height of the object h.

Hope this helps.
 

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