GRADE 12: Energy, Springs and maybe momentum/collisions?

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Homework Help Overview

The problem involves a spring launcher set at an angle, tasked with launching a spring to hit a target at a specific height and horizontal distance. The discussion centers around deriving equations that relate the spring's pullback distance to various parameters including mass, angle, and spring constant.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need for 2D trajectory equations and conservation of mechanical energy principles. There are questions about how to approach the problem without knowing the velocity of the spring at launch.

Discussion Status

Some participants have provided guidance on relevant equations and concepts, while others are exploring the implications of the initial and final heights in the trajectory analysis. There is an ongoing inquiry into how to proceed without certain variables being defined.

Contextual Notes

Participants note the complexity introduced by the differing initial and final heights in the projectile motion context, which may affect the trajectory calculations. There is also mention of the SUVAT equations as a potential reference point for understanding motion under constant acceleration.

michael simone
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Homework Statement


A spring of mass “m” is put on a launcher elevated at “θ” degrees above the horizontal. It is pull back a distance “x” and launched at a target that must travel vertically “dy“ and a horizontal distance of “dx”. The spring has a constant of “k”.Derive an equation (or series of equations) given m, θ, dy ,dx, k so you can calculate a value of x.Example The target is 3.5 m away and the launder is elevated at 30o and it is 1.2 m high, the mass of the spring is 4.5 g, what distance should the spring be pulled back to land in a target that is 0.40 m tall if k = 18 N/m?

Homework Equations


PTi= PTf
Ei=Ef
ENERGY
KINETIC (Ek)
Ek=1/2 MV^2
SPRINGS(elastic Ee)
Ee=1/2 KX^2
E1=E2 IE
Potential (Eg)
Eg= mgh or mg(delta y)
vx= vicos (theta)
Projectile motion and Energy[/B]

The Attempt at a Solution

 
Last edited:
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Check your textbook for 1) 2D trajectory equations and 2) the conservation of mechanical energy. You will need both.
 
Dr Dr news said:
Check your textbook for 1) 2D trajectory equations and 2) the conservation of mechanical energy. You will need both.
ENERGY
KINETIC (Ek)
1/2 MV^2
SPRINGS(elastic Ee)
1/2 KX^2
E1=E2 IE
Potential (Eg)
mgh or mg(delta y)
vx= vicos (theta)
 
The classical range equation is based on the initial elevation and the final elevation both being on the ground. In your problem you have an initial height as well as a final height which means you need to carry them along in your trajectory analysis.
 
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Likes   Reactions: michael simone
thanks for that tip, but how do i slove this when v is not provided.
 

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